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A bag contains 3 white and n red marbles, n > 3. Two marbles are drawn
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16 Nov 2023, 02:24
16 Nov 2023, 02:24
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57% (02:12) wrong based on 7 sessions
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A bag contains 3 white and n red marbles, n > 3. Two marbles are drawn from the bag. If the probability that one marble is white and the other is red is greater than the probability that both the marbles are red, what could be value of n?
Indicate all possible values.
(A) 2
(B) 3
(C) 4
(D) 5
(E) 6
Indicate all possible values.
(A) 2
(B) 3
(C) 4
(D) 5
(E) 6
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Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
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Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
GRE - Math Book
Re: A bag contains 3 white and n red marbles, n > 3. Two marbles are drawn
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16 Nov 2023, 21:04
16 Nov 2023, 21:04
1
n>3
n=4
(4/7*3/6)*2>4/7*3/6
24/42>12/42
n=5
(5/8*3/7)*2>5/8*4/7
30/56>20/56
n=6
(6/9*3/8)*2>6/9*5/8
36/72>30/72
Ans C,D,E
n=4
(4/7*3/6)*2>4/7*3/6
24/42>12/42
n=5
(5/8*3/7)*2>5/8*4/7
30/56>20/56
n=6
(6/9*3/8)*2>6/9*5/8
36/72>30/72
Ans C,D,E
Re: A bag contains 3 white and n red marbles, n > 3. Two marbles are drawn
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04 Dec 2023, 06:36
04 Dec 2023, 06:36
1
(3C1*nC1)/(3+n)C2 > nC2/(3+n)C2
=3*n > n(n-1)/2
=6n > n^2-n
=7n > n^2
=n < 7
thus : 7 > n > 3 (C,D,E)
=3*n > n(n-1)/2
=6n > n^2-n
=7n > n^2
=n < 7
thus : 7 > n > 3 (C,D,E)
