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m^2+n<0 and mn is different from zero
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21 Dec 2023, 06:32
21 Dec 2023, 06:32
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Question Stats:
42% (01:16) correct
57% (01:35) wrong based on 7 sessions
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\(m^2+n<0 \) and \(mn \neq 0\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(\dfrac{m^2}{n} \) |
\(-1\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Free Materials for the GRE General Exam - Where to get it!!
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Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
GRE - Math Book
Re: m^2+n<0 and mn is different from zero
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22 Dec 2023, 14:32
22 Dec 2023, 14:32
1
Since m2+n<0 and mn≠0, it means both m & n are negative integers. So when they divide each other in m2/n, it produces a positive integer which is greater than -1
gmatclubot
Re: m^2+n<0 and mn is different from zero [#permalink]
22 Dec 2023, 14:32
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