the prime factors of 60 are $= 2^2*5*3$

The prime factors of 450 are $= 2*5^2*3^2$

We do know that C to be divisible by 450 and has the same prime factors of 60 + some other factor

if we combine just the information above we do know that C is at least composed by the following factors

$2^3*3^3*5^3 = 9000$

$\frac{9000}{450}$ must be a prime < 100

$\frac{9000}{450 }=20$ and we do know that C is a prime < 100 and has also some other factor that 60 does not have.

Therefore our prime is at least 23 and C results to be > 9000

A is the answer