Carcass wrote:
If a square mirror has a 20-inch diagonal, what is the approximate perimeter of the mirror, in inches?
(A) 40
(B) 60
(C) 80
(D) 100
(E) 120
Let x = the length of one side of the squareThe diagonal creates a
right triangle with each leg having length x and the hypotenuse with length 20.
Plug these values into the Pythagorean Theorem to get: x² + x² = 20²
Simplify: 2x² = 400
Divide both sides by 2 to get x² = 200
So, x = √200
Rewrite as x = 10√2
NOTE: For the GRE, you should memorize approximations for √2, √3 and √5
√2 ≈ 1.4
So, 10√2 ≈ (10)1.4 ≈ 14If each side of the square has length 14, then the perimeter of the square = (4)(14) = 56
The best approximation is B (60)
Cheers,
Brent