GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Joe always runs around the track at a rate of 30 laps per 75 minutes,
[#permalink]
26 Dec 2023, 00:48
26 Dec 2023, 00:48
Expert Reply
00:00
Question Stats:
64% (01:58) correct
35% (02:15) wrong based on 14 sessions
Hide Show timer Statistics
Joe always runs around the track at a rate of 30 laps per 75 minutes, and Carl always runs around the track at a rate of 20 laps per 40 minutes. They start running at the same time.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
Time taken, in minutes, for Joeand Carl to run a combined distance of 99 laps |
222.75 minutes |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Part of the project: The Butler-GRE Daily New Quant and Verbal Questions to Practice (2023) - Gain 20 Kudos & Get FREE Access to GRE Prep Club TESTS
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
GRE - Math Book
Re: Joe always runs around the track at a rate of 30 laps per 75 minutes,
[#permalink]
06 Jan 2024, 23:03
06 Jan 2024, 23:03
1
joe 30 laps in 75 min
carl 20 lap in 40 mins
joe 20 laps in = 75/30 * 20 = 50 min
therefore 40 laps of joe = 100 mins , 40 laps of carl = 80 mins
19 laps remaining, 10 laps of carl = 20 mins, 9 laps of joe = 22. 5 mins
joe total time for 49 laps =100+22.5 = 122.5 mins
carl total time for 50 laps = 80 + 20 = 100 mins
122.5 + 100 = 222.5 mins
QA<QB
carl 20 lap in 40 mins
joe 20 laps in = 75/30 * 20 = 50 min
therefore 40 laps of joe = 100 mins , 40 laps of carl = 80 mins
19 laps remaining, 10 laps of carl = 20 mins, 9 laps of joe = 22. 5 mins
joe total time for 49 laps =100+22.5 = 122.5 mins
carl total time for 50 laps = 80 + 20 = 100 mins
122.5 + 100 = 222.5 mins
QA<QB
Manager
Joined: 11 Nov 2023
Posts: 220
Given Kudos: 78
WE:Business Development (Advertising and PR)
Re: Joe always runs around the track at a rate of 30 laps per 75 minutes,
[#permalink]
09 Jan 2024, 20:26
09 Jan 2024, 20:26
1
Distance = Rate x Time, or Rate = Distance/Time
Joe's rate = 30 laps / 75 min = 0.4 laps / min
Carl's rate = 20 laps / 40 min = 0.5 laps / min
Since they start at the same time and it's asking for a combined distance of 99 laps, plug the rates back in:
(Joe's rate + Carl's rate) * time = 99 laps
(0.4 + 0.5) laps/min * time = 99 laps
time = 110 min
Joe's rate = 30 laps / 75 min = 0.4 laps / min
Carl's rate = 20 laps / 40 min = 0.5 laps / min
Since they start at the same time and it's asking for a combined distance of 99 laps, plug the rates back in:
(Joe's rate + Carl's rate) * time = 99 laps
(0.4 + 0.5) laps/min * time = 99 laps
time = 110 min
