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3<m<8
[#permalink]
10 Jan 2024, 09:39
10 Jan 2024, 09:39
Expert Reply
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Question Stats:
50% (01:14) correct
50% (00:45) wrong based on 20 sessions
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\(3<m<8\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\([\frac{m}{8}]^2\) |
\([\frac{m}{0.08}]^2\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Part of the project: The Butler-GRE Daily New Quant and Verbal Questions to Practice (2023) - Gain 20 Kudos & Get FREE Access to GRE Prep Club TESTS
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Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
GRE - Math Book
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Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
GRE - Math Book
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Joined: 11 Nov 2023
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3<m<8
[#permalink]
11 Jan 2024, 12:36
11 Jan 2024, 12:36
1
Quantity A: \((\frac{m}{8})^2 = (m * 0.125)^2 = m^2 * 0.125^2 = m^2 * 0.015625\)
Quantity B: \((\frac{m}{0.08})^2 = (m * 12.5)^2 = m^2 * 12.5^2 = m^2 * 156.25\)
Regardless of the value of m, quantity B will always be greater.
A good rule of thumb: the square of a value greater than 1 will always be become larger, while the square of a value between 0 and 1 will always become smaller.
Quantity B: \((\frac{m}{0.08})^2 = (m * 12.5)^2 = m^2 * 12.5^2 = m^2 * 156.25\)
Regardless of the value of m, quantity B will always be greater.
A good rule of thumb: the square of a value greater than 1 will always be become larger, while the square of a value between 0 and 1 will always become smaller.
gmatclubot
3<m<8 [#permalink]
11 Jan 2024, 12:36
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