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1/7 of the x devices produced by a manufacture were defective
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31 Jan 2024, 03:54
31 Jan 2024, 03:54
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Question Stats:
86% (01:51) correct
13% (01:36) wrong based on 15 sessions
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1/7 of the x devices produced by a manufacturer were defective and thus disregarded. 70% of the remaining were sold
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The number of the NON defective devices that were not sold |
\( \frac{1}{4}X \) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Re: 1/7 of the x devices produced by a manufacture were defective
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31 Jan 2024, 10:34
31 Jan 2024, 10:34
1
If 1/7 of x devices were defective, then (1 - 1/7) = 6/7 of x were NON defective.
If 7/10 of the NON defective devices were sold, then (1 - 7/10) = 3/10 of them were NOT sold.
Thus, the number of NON defective devices that were NOT sold = 6/7 * 3/10 * x = 18/70x
18/70 > 1/4, so Quantity A is greater.
If 7/10 of the NON defective devices were sold, then (1 - 7/10) = 3/10 of them were NOT sold.
Thus, the number of NON defective devices that were NOT sold = 6/7 * 3/10 * x = 18/70x
18/70 > 1/4, so Quantity A is greater.
Re: 1/7 of the x devices produced by a manufacture were defective
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18 Feb 2024, 18:53
18 Feb 2024, 18:53
I chose numbers.
I made x = 35.
1/7 were defective and tossed out (5).
The rest were non-defective (30). 70% were sold (21). The rest were not (9).
If you plug 35 into Option B, you get 8.75 which is smaller than Option A (9).
A is greater.
I made x = 35.
1/7 were defective and tossed out (5).
The rest were non-defective (30). 70% were sold (21). The rest were not (9).
If you plug 35 into Option B, you get 8.75 which is smaller than Option A (9).
A is greater.
