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The set S is the set of all odd integers
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Updated on: 14 Feb 2024, 04:40
Updated on: 14 Feb 2024, 04:40
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Question Stats:
21% (00:56) correct
78% (01:04) wrong based on 19 sessions
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The set S is the set of all odd integers, and a and b are two elements of set S. Which of the following must also be an element of set S?
Indicate all that apply:
A) \(a + b\)
B) \(a - b\)
C) \(ab\)
D) \(\frac{a}{b}\)
E) \(a^b\)
Indicate all that apply:
A) \(a + b\)
B) \(a - b\)
C) \(ab\)
D) \(\frac{a}{b}\)
E) \(a^b\)
Re: The set S is the set of all odd integers
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05 Oct 2019, 00:44
05 Oct 2019, 00:44
Expert Reply
1-3-5-7-9-11 or using the number property of the odd
A. \(O+O=E\) wrong
B. \(O-O=E\) wrong
C. \(O\times O= O\) Correct
D. \(\frac{O}{O}\) = Odd however we can also have a NON -integer
E. \(O^O = O\) correct
Answers are C and E.
However, something I think is not formulated well into the question
A. \(O+O=E\) wrong
B. \(O-O=E\) wrong
C. \(O\times O= O\) Correct
D. \(\frac{O}{O}\) = Odd however we can also have a NON -integer
E. \(O^O = O\) correct
Answers are C and E.
However, something I think is not formulated well into the question
Re: The set S is the set of all odd integers
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10 Feb 2024, 09:17
10 Feb 2024, 09:17
1
how can E be correct, lets say a=3, b=-1
In this case a^b = 3^-1
which is equal to [1/3] and that wont be in the set S
In this case a^b = 3^-1
which is equal to [1/3] and that wont be in the set S
