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a set has exactly five consecutive integers
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22 Feb 2024, 01:20
22 Feb 2024, 01:20
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A set has exactly five consecutive integers
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The percentage change in the average of the numbers when one of the numbers is dropped from the set |
20 % |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Re: a set has exactly five consecutive integers
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23 Feb 2024, 11:53
23 Feb 2024, 11:53
2
I believe this only works when the first integer in the set isn't zero, right?
If it is 0, then the average of the five consecutive integers would be 10 and the average would be 2.
If you dropped 0, the average of the remaining 4 would be 2.5 and the percent change in the averages would be (2.5-2)/2 = 25%, which is greater than 20%.
Likewise, if you dropped 4 (the 5th consecutive integer), the average would be 1.5 and the percent change in the averages would also be 25%.
If it is 0, then the average of the five consecutive integers would be 10 and the average would be 2.
If you dropped 0, the average of the remaining 4 would be 2.5 and the percent change in the averages would be (2.5-2)/2 = 25%, which is greater than 20%.
Likewise, if you dropped 4 (the 5th consecutive integer), the average would be 1.5 and the percent change in the averages would also be 25%.
Re: a set has exactly five consecutive integers
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20 Jan 2025, 02:45
20 Jan 2025, 02:45
nurirachel wrote:
I believe this only works when the first integer in the set isn't zero, right?
If it is 0, then the average of the five consecutive integers would be 10 and the average would be 2.
If you dropped 0, the average of the remaining 4 would be 2.5 and the percent change in the averages would be (2.5-2)/2 = 25%, which is greater than 20%.
Likewise, if you dropped 4 (the 5th consecutive integer), the average would be 1.5 and the percent change in the averages would also be 25%.
If it is 0, then the average of the five consecutive integers would be 10 and the average would be 2.
If you dropped 0, the average of the remaining 4 would be 2.5 and the percent change in the averages would be (2.5-2)/2 = 25%, which is greater than 20%.
Likewise, if you dropped 4 (the 5th consecutive integer), the average would be 1.5 and the percent change in the averages would also be 25%.
What if it was -2, -1, 0, 1, 2 rather than 0, 1, 2, 3, 4? What could we say?
