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If K=1/2+1/2^2+1/2^3+1/2^4
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01 Mar 2024, 02:07
01 Mar 2024, 02:07
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60% (01:46) correct
39% (02:10) wrong based on 43 sessions
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If \(K=\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+\frac{1}{2^4} \), then the value of K lies between
Indicate al that apply
A. 0 and 7/9
B. 1/10 and 12/17
C. 1/4 and 17/18
D. 3/10 and 23/21
E. 11/12 and 23/21
Indicate al that apply
A. 0 and 7/9
B. 1/10 and 12/17
C. 1/4 and 17/18
D. 3/10 and 23/21
E. 11/12 and 23/21
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Re: If K=1/2+1/2^2+1/2^3+1/2^4
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01 Mar 2024, 14:11
01 Mar 2024, 14:11
2
\(K = \frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+\frac{1}{2^4} \)
\(=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\)
\(=\frac{8}{16}+\frac{4}{16}+\frac{2}{8}+\frac{1}{16}\)
\(=\frac{15}{16} = 0.9375\)
7/9 = 0.78, so A is not an answer.
12/17 = 0.71, so B is not an answer.
\(=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\)
\(=\frac{8}{16}+\frac{4}{16}+\frac{2}{8}+\frac{1}{16}\)
\(=\frac{15}{16} = 0.9375\)
7/9 = 0.78, so A is not an answer.
12/17 = 0.71, so B is not an answer.
Re: If K=1/2+1/2^2+1/2^3+1/2^4
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30 Mar 2026, 09:19
30 Mar 2026, 09:19
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