GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Sep 28Live Online Class with Top GRE Expert Mike Butville
08:00 PM EDT
-10:00 PM EDT
Top scores are possible when you enroll in a powerful GRE course, taught live online + 6 months access to TTP GRE OnDemand video courses included! Class starts Mon/Wed Sept. 28, 2026 - Dec. 9, 2026, 8:00pm-10:00pm EST
x < 0
[#permalink]
15 Sep 2017, 08:07
15 Sep 2017, 08:07
Expert Reply
00:00
Question Stats:
64% (00:56) correct
35% (00:47) wrong based on 88 sessions
Hide Show timer Statistics
\(x < 0\)
Quantity A |
Quantity B |
\(((25^x)^{-2})^3)\) |
\(((5^{-3})^2)^{-x}\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: x < 0
[#permalink]
16 Sep 2017, 08:16
16 Sep 2017, 08:16
1
Using the properties of exponential, we know that if a number is elevated to a and then to b as in (n^a)^b, the exponents can be multiplied and the expression is equal to n^(ab). Thus, in our case we have that column a equals 25^(-6x) and column b equals 5^(6x). Then, given that x<0, this means that 25^(-6x) = 25^(6x), whereas 5^(6x) = 5^(-6x) = 1/5^(6x). Thus, column A is greater and the answer is A.
