Let's use matching operations to move all of the terms to one quantity (see the video lesson below )
Given:
Quantity A: \(\frac{x+4}{x-4}\)
Quantity B: \(x+10\)

Since \(x>4\), we know that \(x-4\) is POSITIVE, which means we can safely multiply both quantities by \(x-4\) to get:
Quantity A: \(x+4\)
Quantity B: \(x^2+6x-40\)

Subtract \(x\) from both quantities and subtract \(4\) from both quantities to get:
Quantity A: \(0\)
Quantity B: \(x^2+5x-44\)

At this point, it's easy to see that, if \(x = 0\), then Quantity A is greater.
And, if \(x = 100\), then Quantity B is greater.

Answer: D

RELATED VIDEO


I don't think the justification here is right to put x=0 since the question clearly says x>4. The other answer seems to be more accurate

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