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In a particular professional club, exactly 75 percent of the female me
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10 Sep 2023, 10:00
10 Sep 2023, 10:00
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35% (02:16) correct
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In a particular professional club, exactly 75 percent of the female members are engineers, and, of them, 1/3 are mechanical engineers. Exactly 30 percent of the male members are engineers. It is known that, only those who are engineers can be mechanical engineers.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
Fraction of the members who are mechanical engineers in the club |
\(\frac{1}{3}\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Re: In a particular professional club, exactly 75 percent of the female me
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24 Sep 2023, 18:05
24 Sep 2023, 18:05
1
Since there's no given numbers, pretend that the total number of members is 200. There are 100 male members and 100 female members.
If there are 100 female members, 75 are engineers (100 * 0.75). Of the 75 engineers, 1/3 are mechanical engineers. 75 * 1/3 = 25. There are 25 female mechanical engineers.
There are 100 male members, 30% are engineers, so 100 * 0. 3 = 30 male engineers. In the scenario that maximizes the number of possible mechanical engineers, say all 30 engineers are also mechanical engineers.
25 + 30 = 55
55/ 200 < 1/3
This means that even in the maximum scenario where all male engineers are mechanical engineers, it is still less than 1/3. Therefore, in all scenarios of male mechanical engineers, the ratio of mechanical engineers to the total organization population will be less than 1/3. Choice B is the answer.
If there are 100 female members, 75 are engineers (100 * 0.75). Of the 75 engineers, 1/3 are mechanical engineers. 75 * 1/3 = 25. There are 25 female mechanical engineers.
There are 100 male members, 30% are engineers, so 100 * 0. 3 = 30 male engineers. In the scenario that maximizes the number of possible mechanical engineers, say all 30 engineers are also mechanical engineers.
25 + 30 = 55
55/ 200 < 1/3
This means that even in the maximum scenario where all male engineers are mechanical engineers, it is still less than 1/3. Therefore, in all scenarios of male mechanical engineers, the ratio of mechanical engineers to the total organization population will be less than 1/3. Choice B is the answer.
Re: In a particular professional club, exactly 75 percent of the female me
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13 Nov 2023, 19:25
13 Nov 2023, 19:25
1
Assum we have 100 female and 100 male with total 200.
Females were 75 eng. and 75/3 = 1/3 M.eng and Males were 30 Eng. so their M.Eng will be a max. less than 1/3-.
so , the total m.eng female + male as maxmiam will less than 1/3 of 200.
Ans: B
Females were 75 eng. and 75/3 = 1/3 M.eng and Males were 30 Eng. so their M.Eng will be a max. less than 1/3-.
so , the total m.eng female + male as maxmiam will less than 1/3 of 200.
Ans: B
