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sqrt 4^{15} + 4^{15} + 4^{15} + 4^{15} =
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05 Sep 2022, 13:48
05 Sep 2022, 13:48
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\(\sqrt{4^{15} + 4^{15} + 4^{15} + 4^{15}} =\)
(A) \(2^8\)
(B) \(2^{15}\)
(C) \(2^{16}\)
(D) \(2^{30}\)
(E) \(2^{32}\)
(A) \(2^8\)
(B) \(2^{15}\)
(C) \(2^{16}\)
(D) \(2^{30}\)
(E) \(2^{32}\)
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sqrt 4^{15} + 4^{15} + 4^{15} + 4^{15} =
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06 Sep 2022, 11:30
06 Sep 2022, 11:30
GreenlightTestPrep wrote:
\(\sqrt{4^{15} + 4^{15} + 4^{15} + 4^{15}} =\)
(A) \(2^8\)
(B) \(2^{15}\)
(C) \(2^{16}\)
(D) \(2^{30}\)
(E) \(2^{32}\)
(A) \(2^8\)
(B) \(2^{15}\)
(C) \(2^{16}\)
(D) \(2^{30}\)
(E) \(2^{32}\)
Using the properties of Exponents:
\(x^ax^b = x^{a+b}\) and \((x^a)^b = x^{ab}\)
\(4^{15} + 4^{15} + 4^{15} + 4^{15} = 4(4^{15}) = 2^2[2^{(2)(15)}] = 2^2(2^{30}) = 2^{2+30} = 2^32\)
Now, \(\sqrt{2^32} = 2^{16}\)
Hence, option C
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Re: sqrt 4^{15} + 4^{15} + 4^{15} + 4^{15} =
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14 Jan 2023, 23:16
14 Jan 2023, 23:16
\(\sqrt{4^{15} + 4^{15} + 4^{15} + 4^{15}}\) = \(\sqrt{4 * 4^{15}}\)
= \(\sqrt{4^{1 + 15}}\) = \(\sqrt{4^{16}}\)
= \(4 ^{\frac{16}{2}}\) = \(4^8\) = \(2^{2*8}\) = \(2^{16}\)
So, Answer will be C
Hope it helps!
Watch the following video to learn the Basics of Exponents
= \(\sqrt{4^{1 + 15}}\) = \(\sqrt{4^{16}}\)
= \(4 ^{\frac{16}{2}}\) = \(4^8\) = \(2^{2*8}\) = \(2^{16}\)
So, Answer will be C
Hope it helps!
Watch the following video to learn the Basics of Exponents
