GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
A sequence of numbers is given as: 1, 2, 2, 3, 3, 3, 4, 4, 4, 4 and so
[#permalink]
13 May 2024, 03:03
13 May 2024, 03:03
1
Expert Reply
1
Bookmarks
00:00
Question Stats:
77% (01:45) correct
22% (02:25) wrong based on 35 sessions
Hide Show timer Statistics
A sequence of numbers is given as: 1, 2, 2, 3, 3, 3, 4, 4, 4, 4 and so on. What will be the 100th term of this sequence?
A. 11
B. 12
C. 13
D. 14
E. 15
A. 11
B. 12
C. 13
D. 14
E. 15
Part of the project: GRE Quant & Verbal ADVANCED Daily Challenge 2024 Edition - Gain 20 Kudos & Get FREE Access to GRE Prep Club TESTS
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Free Materials for the GRE General Exam - Where to get it!!
Shorter GRE - Preparing for the Quantitative Reasoning Measure
Shorter GRE - Preparing for the Verbal Reasoning Measure
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Free Materials for the GRE General Exam - Where to get it!!
Shorter GRE - Preparing for the Quantitative Reasoning Measure
Shorter GRE - Preparing for the Verbal Reasoning Measure
Re: A sequence of numbers is given as: 1, 2, 2, 3, 3, 3, 4, 4, 4, 4 and so
[#permalink]
19 May 2024, 17:21
19 May 2024, 17:21
Is there a way to solve this problem quicker besides writing out the terms?
A sequence of numbers is given as: 1, 2, 2, 3, 3, 3, 4, 4, 4, 4 and so
[#permalink]
19 May 2024, 23:02
19 May 2024, 23:02
1
Expert Reply
Of course . Using observation and logic.
Notice how the sequence has as first term 1 then 2 but two times and then three three times , 4 four times............until k which is the 100 terms
This mean that using the formula for sum of an arithmetic progression we can find easily the solution
\(\frac{k(k+1)}{2}\) why ? every term after the previous June is oNE more
Picking number for example C we do have 13*14/2=91 and the answer is D or E
We need a value a bit bigger (100) so the answer is D
Notice how the sequence has as first term 1 then 2 but two times and then three three times , 4 four times............until k which is the 100 terms
This mean that using the formula for sum of an arithmetic progression we can find easily the solution
\(\frac{k(k+1)}{2}\) why ? every term after the previous June is oNE more
Picking number for example C we do have 13*14/2=91 and the answer is D or E
We need a value a bit bigger (100) so the answer is D
