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n is a positive odd integer
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26 May 2024, 22:02
26 May 2024, 22:02
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Question Stats:
42% (01:42) correct
57% (01:16) wrong based on 28 sessions
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n is a positive odd integer, \(a = \frac{n-1}{2}\) and \(b = \frac{n+1}{2}\)
Quantity A |
Quantity B |
\(-2^a\) |
\(-2^b \) |
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Shorter GRE - Preparing for the Quantitative Reasoning Measure
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Re: n is a positive odd integer
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27 May 2024, 15:03
27 May 2024, 15:03
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Okay, if we make a table I think it would be easier.
n=1
a=0
b=1
A= -2^0=-1
B=-2^1= -2
n=3
a=1
b=2
A= -2^1=-2
B= -2^2=-4
Since a is always going to be smaller than b, the correct answer is A. The tricky part is differentiating -2^n and (-2)^n (I fell for it haha)
n=1
a=0
b=1
A= -2^0=-1
B=-2^1= -2
n=3
a=1
b=2
A= -2^1=-2
B= -2^2=-4
Since a is always going to be smaller than b, the correct answer is A. The tricky part is differentiating -2^n and (-2)^n (I fell for it haha)
Re: n is a positive odd integer
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02 Jun 2024, 01:31
02 Jun 2024, 01:31
1
LuisMartinez wrote:
Okay, if we make a table I think it would be easier.
n=1
a=0
b=1
A= -2^0=-1
B=-2^1= -2
n=3
a=1
b=2
A= -2^1=-2
B= -2^2=-4
Since a is always going to be smaller than b, the correct answer is A. The tricky part is differentiating -2^n and (-2)^n (I fell for it haha)
n=1
a=0
b=1
A= -2^0=-1
B=-2^1= -2
n=3
a=1
b=2
A= -2^1=-2
B= -2^2=-4
Since a is always going to be smaller than b, the correct answer is A. The tricky part is differentiating -2^n and (-2)^n (I fell for it haha)
-2^0 is 1 not -1, -2^2 is 4 not -4 answer should be D,
