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If an integer divisible
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10 Jun 2021, 18:52
10 Jun 2021, 18:52
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If an integer divisible by 8 and 18, then the integer also must be divisible by
A) 12
B) 26
C) 27
D) 30
E) 32
A) 12
B) 26
C) 27
D) 30
E) 32
If an integer divisible
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Updated on: 02 Jul 2021, 08:31
Updated on: 02 Jul 2021, 08:31
2
LCM of 8 and 18 is = 72
From the options given 72 is only divisible by 12
Hence, the answer is A
From the options given 72 is only divisible by 12
Hence, the answer is A
Originally posted by surabhipant on 11 Jun 2021, 04:40.
Last edited by surabhipant on 02 Jul 2021, 08:31, edited 1 time in total.
Last edited by surabhipant on 02 Jul 2021, 08:31, edited 1 time in total.
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If an integer divisible
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02 Jul 2021, 07:46
02 Jul 2021, 07:46
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Theory: If an integer is divisible by two numbers then the integer will also be divisible by the LCM of these two number.
If an integer divisible by 8 and 18, then the integer also must be divisible by LCM(8,18)
Using Long Division Method
2 | 8 , 18
-----------
| 4 , 9
=> LCM (8,18) = 2*4*9 = 72
Since the integer is divisible by 72 then it will also be divisible by factors of 72. Only factor of 72 in the answer choices is 12
So, Answer will be A
Hope it helps!
To learn more about LCM and GCD watch the following videos
If an integer divisible by 8 and 18, then the integer also must be divisible by LCM(8,18)
Using Long Division Method
2 | 8 , 18
-----------
| 4 , 9
=> LCM (8,18) = 2*4*9 = 72
Since the integer is divisible by 72 then it will also be divisible by factors of 72. Only factor of 72 in the answer choices is 12
So, Answer will be A
Hope it helps!
To learn more about LCM and GCD watch the following videos
