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Area of circle with radius [square_root]7[/square_root]
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21 Jun 2018, 02:21
21 Jun 2018, 02:21
2
00:00
Question Stats:
89% (00:34) correct
10% (00:21) wrong based on 49 sessions
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Quantity A |
Quantity B |
Area of circle with radius \(\sqrt{7}\) |
Area of circle with diameter \(\sqrt{14}\) |
A The quantity in Column A is greater
B The quantity in Column B is greater
C The two quantities are equal
D The relationship cannot be determined from the information given
Re: Area of circle with radius [square_root]7[/square_root]
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22 Jun 2018, 07:38
22 Jun 2018, 07:38
1
amorphous wrote:
Quantity A |
Quantity B |
Area of circle with radius \(\sqrt{7}\) |
Area of circle with diameter \(\sqrt{14}\) |
For statement 1,
We know area of the circle = π \(r^2\)
= π \((\sqrt{7})^2\)
= 7π
In Statement 2,
We know area of the circle = π \(r^2\)
= π \((\sqrt{14})/2)^2\) (Since here diameter is given so we divide it by 2 to get the radius)
= \(\frac{14}{4}\) π
= \(\frac{7}{2}\) π, which is less than statement 1
Hence option A
Re: Area of circle with radius [square_root]7[/square_root]
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19 Jan 2019, 10:25
19 Jan 2019, 10:25
B has radius sqrt14/2<sqrt7
that gives area A> area B
that gives area A> area B
