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A candy jar has 4 lime, 10 cherry, 8 orange, and x grape ca
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06 Jun 2017, 06:40
06 Jun 2017, 06:40
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Question Stats:
58% (01:21) correct
41% (01:28) wrong based on 161 sessions
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A candy jar has 4 lime, 10 cherry, 8 orange, and x grape candies. If Tom selects a candy from the jar at random and the probability that he selects an orange candy is greater than 20 percent, which of the following could be the value of x ?
Indicate all such values.
❑ 10
❑ 14
❑ 18
❑ 22
❑ 24
❑ 28
Re: A candy jar has 4 lime, 10 cherry, 8 orange, and x grape ca
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21 Sep 2017, 06:06
21 Sep 2017, 06:06
1
Since we know that the probability of extracting a orange candy is greater than 20%, we can rewrite this information as \(\frac{8}{22+x}>0.2\). In other words, there are eight favorable cases, the eight orange candies out of a total number of cases equal to the total number of candies. Now, we just have to substitute x with the provided answers to get that only A and B satisfies the inequality above.
Re: A candy jar has 4 lime, 10 cherry, 8 orange, and x grape ca
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26 Mar 2018, 20:08
26 Mar 2018, 20:08
why can't we solve the inequality and get x<28 as the answer?
