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Number N = 9 × 27 × 243 × 729. Which of the following options are tru
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13 Jun 2024, 04:58
13 Jun 2024, 04:58
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Question Stats:
75% (01:14) correct
25% (00:43) wrong based on 8 sessions
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Number \(N = 9 × 27 × 243 × 729\). Which of the following options are true?
A. \(N=3^{16}\)
B.\( N=p \times q\) , where \(p=9^8\) and \(q=9^8\)
C. \(N=9^{16}\)
D. \(N=9^8\)
A. \(N=3^{16}\)
B.\( N=p \times q\) , where \(p=9^8\) and \(q=9^8\)
C. \(N=9^{16}\)
D. \(N=9^8\)
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Shorter GRE - Preparing for the Quantitative Reasoning Measure
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Free Materials for the GRE General Exam - Where to get it!!
Shorter GRE - Preparing for the Quantitative Reasoning Measure
Shorter GRE - Preparing for the Verbal Reasoning Measure
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Joined: 25 Jul 2020
Posts: 36
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GRE 1: Q170 V157
Re: Number N = 9 × 27 × 243 × 729. Which of the following options are tru
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16 Jun 2024, 04:43
16 Jun 2024, 04:43
1
First: options A and D are identical, and same for options B and C. So you have really only two choices.
With that in mind, find N:
N = 3^2 \times 3^3 \times 3^5 \times 3^6\
N = 3^{2 + 3 + 5 + 6}
N = 3^{16}
which makes the correct pair of options A and D (as 9^8 = (3^2)^8 = 3^{16}).
With that in mind, find N:
N = 3^2 \times 3^3 \times 3^5 \times 3^6\
N = 3^{2 + 3 + 5 + 6}
N = 3^{16}
which makes the correct pair of options A and D (as 9^8 = (3^2)^8 = 3^{16}).
gmatclubot
Re: Number N = 9 × 27 × 243 × 729. Which of the following options are tru [#permalink]
16 Jun 2024, 04:43
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