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Jake rides his bike for the first
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19 Aug 2017, 08:13
19 Aug 2017, 08:13
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Question Stats:
75% (02:57) correct
24% (02:37) wrong based on 137 sessions
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Jake rides his bike for the first \(\frac{2}{3}\) of the distance from home to school, traveling at 10 miles per hour. He then walks the remaining \(\frac{1}{3}\) of the distance at 3 miles per hour. If his total trip takes 40 minutes, how many miles is it from Jake's home to his school?
A. \(\frac{5}{4}\)
B. \(\frac{15}{4}\)
C. 5
D. 6
E. 10
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Re: Jake rides his bike for the first
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28 Aug 2017, 15:00
28 Aug 2017, 15:00
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Carcass wrote:
Jake rides his bike for the first \(\frac{2}{3}\) of the distance from home to school, traveling at 10 miles per hour. He then walks the remaining \(\frac{1}{3}\) of the distance at 3 miles per hour. If his total trip takes 40 minutes, how many miles is it from Jake's home to his school?
A. \(\frac{5}{4}\)
B. \(\frac{15}{4}\)
C. 5
D. 6
E. 10
A. \(\frac{5}{4}\)
B. \(\frac{15}{4}\)
C. 5
D. 6
E. 10
Let's start with a word equation.
(time spent on bike) + (time spent walking) = 2/3 hours (= 40 minutes)
Let D = total distance (in miles) from home to school
So, Jake rode his bike for a distance of (2/3)D miles, which equals 2D/3 miles
Then Jake walked for a distance of (1/3)D miles, which equals D/3 miles
Time = distance/rate
So, we can write: (2D/3)/10 + (D/3)/3 = 2/3
Multiply both sides by 30 to get: 6D/3 + 10D/3 = 60/3
Multiply both sides by 3 to get: 6D + 10D = 60
Simplify: 16D = 60
Solve: D = 60/16 = 30/8 = 15/4
Answer: B
Cheers,
Brent
Re: Jake rides his bike for the first
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16 Jun 2024, 12:23
16 Jun 2024, 12:23
I didnot understood the calculations. please explain
