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Re: If a + b < 0 and a + 2b = 3, then which of the following must be true? [#permalink]
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From a + 2b = 3 we get that b = (3 - a)/2.

Substitute b = (3 - a)/2 into a + b < 0 to get a + (3 - a)/2 < 0. This simplifies in a < -3.

Now, if a < -3, then a is also less than -2.

Answer: C.
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Re: If a + b < 0 and a + 2b = 3, then which of the following must be true? [#permalink]
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given a+b<0
so sum is -ve and a+2b=3
let a = -5 and b = 4
option C a<-2 is correct
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Re: If a + b < 0 and a + 2b = 3, then which of the following must be true? [#permalink]
1
Here's the step-by-step solution:

1. From the second equation, we can express a in terms of b:
a + 2b = 3 implies a = 3 - 2b

2. Substitute a = 3 - 2b into the inequality a + b < 0:

(3 - 2b) + b < 0

Simplify the inequality:

3 - b < 0 \implies 3 < b \implies b > 3


3. Since b > 3, substitute back into a = 3 - 2b:

a = 3 - 2b

Since b > 3, we can infer that 2b > 6. Thus:

a = 3 - 2b < 3 - 6 = -3


Therefore, a < -3.

Among the given options, the one that is consistent with a < -3 is answer C a < -2
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