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x and y are integers and x > y. x² + y² = 25
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Updated on: 29 Jun 2024, 09:07
Updated on: 29 Jun 2024, 09:07
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Question Stats:
87% (01:23) correct
12% (00:18) wrong based on 8 sessions
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x and y are integers and \(x > y\).
\(x^2 + y^2 = 25\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
\(x^2 + y^2 = 25\)
Quantity A |
Quantity B |
x |
4 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Originally posted by itwasmaroon on 28 Jun 2024, 15:05.
Last edited by Carcass on 29 Jun 2024, 09:07, edited 2 times in total.
Last edited by Carcass on 29 Jun 2024, 09:07, edited 2 times in total.
UPDATED
Re: x and y are integers and x > y. x² + y² = 25
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29 Jun 2024, 10:18
29 Jun 2024, 10:18
Expert Reply
Square the equation
\(\sqrt{x^2+y^2}=\sqrt{25}\)
x+y=5
we do know that x>y and they are integers
we can have the following scenarios
3+2=5 and x is =3 and the answer is B
or
5+0 and x is =5 and the answer is A
D is the definitive answer
\(\sqrt{x^2+y^2}=\sqrt{25}\)
x+y=5
we do know that x>y and they are integers
we can have the following scenarios
3+2=5 and x is =3 and the answer is B
or
5+0 and x is =5 and the answer is A
D is the definitive answer
Re: x and y are integers and x > y. x² + y² = 25
[#permalink]
29 Jun 2024, 11:48
29 Jun 2024, 11:48
sqrt(x^2+y^2) != x + y Carcass
