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If S is the point (4, 1), T is the point (–2, y), and the sl
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08 Jan 2021, 10:24
08 Jan 2021, 10:24
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If S is the point (4, 1), T is the point (–2, y), and the slope of \(\overline{ST} = \frac{2}{3}\) , find y
A. 5
B. 2
C. 0
D. –3
E. –8
Kudos for the right answer and explanation
A. 5
B. 2
C. 0
D. –3
E. –8
Kudos for the right answer and explanation
If S is the point (4, 1), T is the point (–2, y), and the sl
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09 Jan 2021, 08:32
09 Jan 2021, 08:32
2
Slope can be found with two co-ordinates as well.
Slope = \(\frac{Y2 - Y1 }{ X2 - X1}\)
Points are (4,1) & (-2,y)
Here slope = \(\frac{2}{3}\) = \(\frac{y-1}{-2-4}\)
\(\frac{2}{3}\) = \(\frac{y-1}{-6}\)
\(-4 = y-1\)
\(y = -3\)
Answer D
Slope = \(\frac{Y2 - Y1 }{ X2 - X1}\)
Points are (4,1) & (-2,y)
Here slope = \(\frac{2}{3}\) = \(\frac{y-1}{-2-4}\)
\(\frac{2}{3}\) = \(\frac{y-1}{-6}\)
\(-4 = y-1\)
\(y = -3\)
Answer D
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If S is the point (4, 1), T is the point (2, y), and the sl
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06 Jul 2024, 04:22
06 Jul 2024, 04:22
1
↧↧↧ Detailed Video Explanation to the Problem ↧↧↧
Given that S is the point (4, 1), T is the point (–2, y), and the slope of \(\overline{ST} = \frac{2}{3}\), and we need to find y
Slope of a line is given by = Difference of y-coordinates/ Difference of x-coordinates
=> Slope of \(\overline{ST}\)= \(\frac{y - 1}{-2 - 4}\) = \(\frac{y - 1}{-6}\) = \(\frac{2}{3}\)
=> y - 1 = -2*2 = -4
=> y = -4 + 1 = -3
So, Answer will be D
Hope it helps!
Watch the following video to MASTER Slope of a Line
Given that S is the point (4, 1), T is the point (–2, y), and the slope of \(\overline{ST} = \frac{2}{3}\), and we need to find y
Slope of a line is given by = Difference of y-coordinates/ Difference of x-coordinates
=> Slope of \(\overline{ST}\)= \(\frac{y - 1}{-2 - 4}\) = \(\frac{y - 1}{-6}\) = \(\frac{2}{3}\)
=> y - 1 = -2*2 = -4
=> y = -4 + 1 = -3
So, Answer will be D
Hope it helps!
Watch the following video to MASTER Slope of a Line
