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30% of the surface area of a right circular cylinder is shad
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22 Apr 2018, 09:20
22 Apr 2018, 09:20
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Question Stats:
63% (01:44) correct
36% (01:39) wrong based on 22 sessions
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30% of the surface area of a right circular cylinder is shaded. If the diameter of the base of the cylinder is 10 and the height is 4, what is the surface area of the unshaded region?
A. \(27\pi\)
B. \(40\pi\)
C. \(63\pi\)
D. \(70\pi\)
E. \(90\pi\)
A. \(27\pi\)
B. \(40\pi\)
C. \(63\pi\)
D. \(70\pi\)
E. \(90\pi\)
Re: 30% of the surface area of a right circular cylinder is shad
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Updated on: 24 Apr 2018, 01:42
Updated on: 24 Apr 2018, 01:42
knowing the formulas for volumes and surface area of solid figure is useful
surface area of a cylinder = 2pi*r(r+h)
since diameter \(= 10\); \(r = 5\)
Find the total surface are of the cylinder \(= 2*pi*5(5+4) = 90pi\)
\(30\)% of \(90pi\) \(= 27pi\) which is the shaded area hence
unshaded area \(= 90pi-27pi = 63pi\)
option c
surface area of a cylinder = 2pi*r(r+h)
since diameter \(= 10\); \(r = 5\)
Find the total surface are of the cylinder \(= 2*pi*5(5+4) = 90pi\)
\(30\)% of \(90pi\) \(= 27pi\) which is the shaded area hence
unshaded area \(= 90pi-27pi = 63pi\)
option c
Re: 30% of the surface area of a right circular cylinder is shad
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24 Apr 2018, 01:43
24 Apr 2018, 01:43
1
Expert Reply
if you use \(\pi\) copying and paste it from the web, then when you wrap it up with \(tag m\) the result are strange symbols.
Instead, just write simply \pi and wrap with \(tag m\)
the result is this \(\pi\)
Instead, just write simply \pi and wrap with \(tag m\)
the result is this \(\pi\)
