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m and n are two positive integers. 5m + 7n = 46.
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04 Apr 2018, 15:11
04 Apr 2018, 15:11
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m and n are two positive integers, and \(5m + 7n = 46\).
A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Quantity A |
Quantity B |
m |
n |
A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Re: m and n are two positive integers. 5m + 7n = 46.
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04 Apr 2018, 15:30
04 Apr 2018, 15:30
4
Answer: A
M and n are positive integers. We should find out all values each of them might have.
5m + 7n = 46, 7n = 46-5m
m ———————- n
1———————— ! _______m=1, 7n = 46- 5*1 -> n = 41/7 !! Not posible as n is not integer
2———————— !________m=2, 7n = 46- 5*2 -> n = 36/7 !! Not posible as n is not integer
3———————— !________m=3, 7n = 46- 5*3 -> n = 31/7 !! Not posible as n is not integer
4———————— ! ________m=4, 7n = 46- 5*4 -> n = 26/7 !! Not posible as n is not integer
5———————— 3________m=5, 7n = 46- 5*5 -> n = 21/7=3 (POSIBLE FOR m=5 and n = 3)
6———————— ! ________m=6, 7n = 46- 5*6 -> n = 16/7 !! Not posible as n is not integer
7———————— ! ________m=7, 7n = 46- 5*7 -> n = 11/7 !! Not posible as n is not integer
8———————— ! ________m=8, 7n = 46- 5*8 -> n = 6/7 !! Not posible as n is not integer.
We can’t go further because n is being a value below 1 while it is an integer number.
So the only possible values for m and n are: m= 5 and n = 3
A is bigger than B and the answer is A.
M and n are positive integers. We should find out all values each of them might have.
5m + 7n = 46, 7n = 46-5m
m ———————- n
1———————— ! _______m=1, 7n = 46- 5*1 -> n = 41/7 !! Not posible as n is not integer
2———————— !________m=2, 7n = 46- 5*2 -> n = 36/7 !! Not posible as n is not integer
3———————— !________m=3, 7n = 46- 5*3 -> n = 31/7 !! Not posible as n is not integer
4———————— ! ________m=4, 7n = 46- 5*4 -> n = 26/7 !! Not posible as n is not integer
5———————— 3________m=5, 7n = 46- 5*5 -> n = 21/7=3 (POSIBLE FOR m=5 and n = 3)
6———————— ! ________m=6, 7n = 46- 5*6 -> n = 16/7 !! Not posible as n is not integer
7———————— ! ________m=7, 7n = 46- 5*7 -> n = 11/7 !! Not posible as n is not integer
8———————— ! ________m=8, 7n = 46- 5*8 -> n = 6/7 !! Not posible as n is not integer.
We can’t go further because n is being a value below 1 while it is an integer number.
So the only possible values for m and n are: m= 5 and n = 3
A is bigger than B and the answer is A.
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Re: m and n are two positive integers. 5m + 7n = 46.
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11 Apr 2020, 06:38
11 Apr 2020, 06:38
1
Carcass wrote:
m and n are two positive integers, and \(5m + 7n = 46\).
Quantity A |
Quantity B |
m |
n |
Given: \(5m + 7n = 46\)
Subtract \(7n\) from both sides of the equation to get: \(5m = 46 - 7n\)
Divide both sides by \(5\) to get: \(m = \frac{46 - 7n}{5}\)
