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Re: A box contains every positive 4-digit integer whose digits add to 34. [#permalink]
1
Two possibilities

8899 number of outcomes 4!/2!2! = 6


9997 number of outcomes 4!/3! = 4

For a number to be divisible by 4, last 2 digits must be a multiple of 4.

Of all the outcomes only 9988 fit.

Answer 1/10

Adewale Fasipe, quant instructor Lagos Nigeria.
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Re: A box contains every positive 4-digit integer whose digits add to 34. [#permalink]
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