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Re: The volume of the rectangular solid above is 720. If AF = 15, which of
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09 Dec 2022, 04:00
Expert Reply
OE
The distance from C to F is the diagonal of the box, so use the Super Pythagorean theorem: a^2 + b^2 + c^2 = d^2, where a, b, and c are the sides of the box and d is the diagonal. You have the length and height of the box, so use the volume formula to find the width: 720 = (15)(6)w, so the width is 8. Now plug your numbers into the formula: 15^2 + 8^2 + 6^2 = d^2, so 325 = d^2, and d = 18.03.
Re: The volume of the rectangular solid above is 720. If AF = 15, which of
[#permalink]
05 Aug 2024, 09:35
Carcass wrote:
OE
The distance from C to F is the diagonal of the box, so use the Super Pythagorean theorem: a^2 + b^2 + c^2 = d^2, where a, b, and c are the sides of the box and d is the diagonal. You have the length and height of the box, so use the volume formula to find the width: 720 = (15)(6)w, so the width is 8. Now plug your numbers into the formula: 15^2 + 8^2 + 6^2 = d^2, so 325 = d^2, and d = 18.03.
Re: The volume of the rectangular solid above is 720. If AF = 15, which of
[#permalink]
05 Aug 2024, 10:36
Expert Reply
we need to find is the longest digonal in this case l*b*h= 720 given l = 15 so b*h = 48 b& h have to be < L so best option 6*8*15 =720 or say √6^2+8^2+15^2 = 18 IMO E