Carcass wrote:
Attachment:
triangle.jpg

Quantity A |
Quantity B |
a + d – c – 90 |
90 – e – b – f |
Given:
Quantity A: a + d – c – 90
Quantity B: 90 – e – b – f
First recognize that, since AC||FD, ∠b = ∠c
So, we can replace b with c to get:
Quantity A: a + d – c – 90
Quantity B: 90 – e – c – f
Add c to both quantities to get:
Quantity A: a + d – 90
Quantity B: 90 – e – f
Now add 90 to both quantities to get:
Quantity A: a + d
Quantity B: 180 – e – f
Now add e and f to both quantities to get:
Quantity A: a + d + e + f
Quantity B: 180
Finally, notice that, since AC||FD, ∠d = ∠BCD
So, replace ∠d with ∠BCD to get:
Quantity A: a + ∠BCD + e + f
Quantity B: 180
At this point, we should recognize that Quantity A represents the sum of all three angles of ∆ACE
As such, Quantity A MUST equal 180
Answer: C
Cheers,
Brent