We know x and $\((\mathrm{x}+2)\)$ are factors of y ; we need to compare the product $\(\mathrm{x}(\mathrm{x}+2)\)$ with y .

Column A and column B will have equal quantities if y is the number having exactly 3 factors 1 . $\(x\)$ and $\((x+2)\)$ (Factors of $\(y\)$ can be exactly 2 if $\(x=1\)$ ) i.e. $\(y\)$ can be 15 , so $\(x=3\)$ or $\(y\)$ can be 35 , so $\(x\)$ $=5$ etc.

But the column B can have higher quantity if y has more factors other than x and $\((\mathrm{x}+2)\)$. For example if $\(y=20\)$ its factors of the form $\(x\)$ and $\((x+2)\)$ are 2 and 4 respectively and we have $\(x(x+2)=2 \times 4=8<y=20\)$

Hence a unique comparison cannot be made between column A and column B quantities, so the answer is (D).