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A pastor divided chocolates between three children, five children and
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19 Aug 2024, 03:16
19 Aug 2024, 03:16
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A pastor divided chocolates between three children, five children and seven children. In each case, he was left with two chocolates. Which of the following options can be the number of chocolates the pastor had at the beginning of distribution?
A. 107
B. 212
C. 103
E. 208
A. 107
B. 212
C. 103
E. 208
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Re: A pastor divided chocolates between three children, five children and
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28 Aug 2024, 15:30
28 Aug 2024, 15:30
1
If you think about this backwards, the possible total number of chocolates MINUS 2 must a multiple of 3, 5, and 7.
Since 3, 5, and 7 are prime numbers, their LCM is 105.
Subtract 2 from each option and divide by 105; if the answer is a whole number, then it is a possible option.
A)
107 - 2 = 105
105 / 105 = 1
A works
B.
212 - 2 = 210
210 / 105 = 2
B works
C.
103 - 2 = 101
101 / 105 = 0.96
C does not work
E.
208 - 2 = 206
206 / 105 = 1.96
D does not work
Since 3, 5, and 7 are prime numbers, their LCM is 105.
Subtract 2 from each option and divide by 105; if the answer is a whole number, then it is a possible option.
A)
107 - 2 = 105
105 / 105 = 1
A works
B.
212 - 2 = 210
210 / 105 = 2
B works
C.
103 - 2 = 101
101 / 105 = 0.96
C does not work
E.
208 - 2 = 206
206 / 105 = 1.96
D does not work
gmatclubot
Re: A pastor divided chocolates between three children, five children and [#permalink]
28 Aug 2024, 15:30
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