Last visit was: 24 Dec 2024, 10:16 |
It is currently 24 Dec 2024, 10:16 |
Customized
for You
Track
Your Progress
Practice
Pays
We need to find the cycle of last two digits of power of 6 | |
\(6^1\) last two digits is 06 \(6^2\) last two digits is 06*6 = 36 \(6^3\) last two digits is 36*6 = 16 \(6^4\) last two digits is 16*6 = 96 \(6^5\) last two digits is 96*6 = 76 \(6^6\) last two digits is 76*6 = 56 | \(6^7\) last two digits is 56*6 = 36 \(6^8\) last two digits is 36*6 = 16 |
|
||
Hi Generic [Bot],Here are updates for you:Prep Club for GRE REWARDS |