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What is the value of a^-0.6
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01 Nov 2021, 06:28
01 Nov 2021, 06:28
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62% (00:39) correct
37% (01:50) wrong based on 8 sessions
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What is the value of a^-0.6
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01 Nov 2021, 19:47
01 Nov 2021, 19:47
\(a^{\frac{1}{5}} = 2\)
\(a^{-0.6}\)
\(= a^{-\frac{6}{10}} = a^{-\frac{3}{5}} = a^{\frac{1}{5} * -3} = 2^{-3} \)
\(\frac{1}{2^3} = \frac{1}{8}\)
Answer \(\frac{1}{8} = 0.125\)
\(a^{-0.6}\)
\(= a^{-\frac{6}{10}} = a^{-\frac{3}{5}} = a^{\frac{1}{5} * -3} = 2^{-3} \)
\(\frac{1}{2^3} = \frac{1}{8}\)
Answer \(\frac{1}{8} = 0.125\)
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Re: What is the value of a^-0.6
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05 Nov 2021, 07:05
05 Nov 2021, 07:05
1
Carcass wrote:
Given: \(\sqrt[5]{a}=2\)
In other words: \(a^{\frac{1}{5}}=2\)
In other words: \(a^{0.2}=2\)
Aside: Our goal is to find the value of \(a^{\frac{1}{5}}=2\)
Raise both sides of our equation by the power of \(3\) to get: \((a^{0.2})^3=2^3\)
Simplify: \(a^{0.6}=8\)
Raise both sides of our equation by the power of \(-1\) to get: \((a^{0.6})^{-1}=8^{-1}\)
Simplify: \(a^{-0.6}=\frac{1}{8}\)
Or we can write: \(a^{-0.6}=0.125\)
Answer: 1/8 or 0.125
