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What is the product of the factors of twice the sum of the roots of th
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17 May 2021, 15:17
17 May 2021, 15:17
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Question Stats:
80% (00:46) correct
20% (01:06) wrong based on 10 sessions
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What is the product of the factors of twice the sum of the roots of the equation \(2x^2 − 4x − 6 = 0\) ?
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Re: What is the product of the factors of twice the sum of the roots of th
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17 May 2021, 23:13
17 May 2021, 23:13
after getting root of equation' what to do?
i lost in sentence ,.....
i lost in sentence ,.....
Re: What is the product of the factors of twice the sum of the roots of th
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18 May 2021, 09:36
18 May 2021, 09:36
2
Wow! Great question.
Read in chunks. Stem is hard to understand but the que is too easy.
(the product of the factors of) twice the sum of the roots of the equation
\(2x^2 - 4x - 6 = 0\)
\(x^2 - 2x - 3 = 0\)
Roots are : \(3\) & \(-1\)
Sum of roots : \(2\)
Twice the sum of roots : \(4\)
We are asked the product of factors oftwice the sum of roots.
So product of factors of \(4\)
Factors of \(4\) : \(1 , 2 , 4\)
Product = \(1 * 2 * 4 =\) \(8\)
Posted from my mobile device
Read in chunks. Stem is hard to understand but the que is too easy.
(the product of the factors of) twice the sum of the roots of the equation
\(2x^2 - 4x - 6 = 0\)
\(x^2 - 2x - 3 = 0\)
Roots are : \(3\) & \(-1\)
Sum of roots : \(2\)
Twice the sum of roots : \(4\)
We are asked the product of factors oftwice the sum of roots.
So product of factors of \(4\)
Factors of \(4\) : \(1 , 2 , 4\)
Product = \(1 * 2 * 4 =\) \(8\)
void wrote:
after getting root of equation' what to do?
i lost in sentence ,.....
i lost in sentence ,.....
Posted from my mobile device
