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For all integers
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10 Feb 2021, 10:23
10 Feb 2021, 10:23
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76% (00:50) correct
23% (00:55) wrong based on 169 sessions
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For all integers \(a\) and \(b\), \(a \vartriangle b = ab + 2(a+b)\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
\( \frac{1}{1 \vartriangle 2 }\) |
\((0 \vartriangle 1 )^ {-3}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
For all integers
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10 Feb 2021, 19:37
10 Feb 2021, 19:37
2
\(a \vartriangle b = ab + 2(a+b)\)
Qt A
\(1 \vartriangle 2\)
= 1*2 + 2(1+2)
= 2 + 6
= 8
Qt A = \(\frac{1}{8}\)
Qt B
\(0 \vartriangle 1\)
= 0*1 + 2(0+1)
= 2
Now, \((2)^ {-3}\)
= \(\frac{1}{8}\)
Qt A = Qt B
Answer C
Qt A
\(1 \vartriangle 2\)
= 1*2 + 2(1+2)
= 2 + 6
= 8
Qt A = \(\frac{1}{8}\)
Qt B
\(0 \vartriangle 1\)
= 0*1 + 2(0+1)
= 2
Now, \((2)^ {-3}\)
= \(\frac{1}{8}\)
Qt A = Qt B
Answer C
Re: For all integers
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24 Oct 2024, 02:45
24 Oct 2024, 02:45
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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