Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized for You
we will pick new questions that match your level based on your Timer History
Track Your Progress
every week, we’ll send you an estimated GRE score based on your performance
Practice Pays
we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
Your score will improve and your results will be more realistic
Is there something wrong with our timer?Let us know!
#GREpracticequestion A rectangular ribbon of width x is wrapped around the right.jpg [ 7.16 KiB | Viewed 15894 times ]
A rectangular ribbon of width x is wrapped around the right circular cylinder with radius n shown above, encircling the cylinder without overlap. The area of the ribbon is equal to the area of the base of the cylinder.
Quantity A
Quantity B
x
n
A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given.
A rectangular ribbon of width x is wrapped around the right circular cylinder with radius n shown above, encircling the cylinder without overlap. The area of the ribbon is equal to the area of the base of the cylinder.
Quantity A
Quantity B
x
n
A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given.
NICE!!!!
AREA OF RIBBON If we remove the ribbon and lay it flat, we see that it is a rectangle. So, to find the area, we need its length and width. The width = x
The length of the ribbon is equal to the circumference of the cylinder. Circumference = 2(pi)(radius) So, the length = 2(pi)(n)
Area of ribbon = (length)(width) = 2(pi)(n)(x)
----------------------------------------- AREA OF CYLINDER BASE The base is a circle Area of circle = (pi)(radius)² So, area of base = (pi)(n)²
The area of the ribbon is equal to the area of the base of the cylinder. We get: 2(pi)(n)(x) = (pi)(n)² To simplify this, first divide both sides by pi to get: 2(n)(x) = (n)² Next, divide both sides by n to get: 2x = n
Great! We're ask to compare the following: Quantity A: x Quantity B: n
Since 2x = n, we can replace n with 2x to get: Quantity A: x Quantity B: 2x Quantity B is greater.