GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
The equation of the curve shown in the xy-plane above is
[#permalink]
06 Jun 2021, 22:20
06 Jun 2021, 22:20
1
Expert Reply
4
Bookmarks
00:00
Question Stats:
66% (01:34) correct
33% (01:25) wrong based on 51 sessions
Hide Show timer Statistics
Attachment:
GRE circle.png [ 13.11 KiB | Viewed 3126 times ]
The equation of the curve shown in the xy-plane above is \( 9x^2+16y^2=144\). Points A, B, C, and D are the x- and y-intercepts of the graph.
Quantity A |
Quantity B |
Length AB |
Length CD |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
Re: The equation of the curve shown in the xy-plane above is
[#permalink]
06 Jun 2021, 23:36
06 Jun 2021, 23:36
2
1
Bookmarks
Carcass wrote:
Attachment:
GRE circle.png
The equation of the curve shown in the xy-plane above is \( 9x^2+16y^2=144\). Points A, B, C, and D are the x- and y-intercepts of the graph.
Quantity A |
Quantity B |
Length AB |
Length CD |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Put \(y = 0\) in the equation to find the x-intercepts
\( 9x^2 = 144\)
\( x^2 = \frac{144}{9}\)
\( x = \sqrt{\frac{144}{9}}\)
\(x = ±\frac{12}{3} = ±4\)
i.e. B = (4, 0) and A = (-4, 0)
Now, Put \(x = 0\) in the equation to find the y-intercepts
\( 16y^2 = 144\)
\( y^2 = \frac{144}{16}\)
\( y = \sqrt{\frac{144}{16}}\)
\(y = ±\frac{12}{4} = ±3\)
i.e. C = (3, 0) and D = (-3, 0)
Col. A: 4 + 4 = 8
Col. B: 3 + 3 = 6
Hence, option A
Re: The equation of the curve shown in the xy-plane above is
[#permalink]
30 Oct 2024, 05:10
30 Oct 2024, 05:10
Hello from the GRE Prep Club BumpBot!
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
