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In △ABC, AB =6, BC = 8, and CA =10.5
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29 Dec 2020, 06:20
29 Dec 2020, 06:20
Expert Reply
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Question Stats:
60% (00:50) correct
40% (03:48) wrong based on 25 sessions
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In △ABC, AB =6, BC = 8, and CA =10.5
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
The measure of angle ABC |
90° |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Re: In △ABC, AB =6, BC = 8, and CA =10.5
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29 Dec 2020, 10:33
29 Dec 2020, 10:33
1
If <ABC would be 90, 6^2 + 8^2 would be equal to 10 = AC.
But here AC is more than 10 that is 10.5
So, <ABC is greater than 90 degree.
Ans: A
But here AC is more than 10 that is 10.5
So, <ABC is greater than 90 degree.
Ans: A
Re: In △ABC, AB =6, BC = 8, and CA =10.5
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30 Dec 2020, 07:55
30 Dec 2020, 07:55
1
Simply use the 3:4:5 right triangle rule.
We see it should have been 6:8:10 but we have 10.5 ; that means hypotenuse is stretched further making angle greater than 90.
Hence A
We see it should have been 6:8:10 but we have 10.5 ; that means hypotenuse is stretched further making angle greater than 90.
Hence A
