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Three friends, R, Y and M, each have a different number of toffees. M
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22 Dec 2023, 01:00
22 Dec 2023, 01:00
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Question Stats:
77% (02:28) correct
22% (03:16) wrong based on 18 sessions
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Three friends, R, Y and M, each have a different number of toffees. M has 1/4 of the total number of toffees all three friends together have and the difference between the number of toffees of Y and R is 1/10 of the total number of toffees.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
Percent of total toffees with the two friends who have the least number of toffees |
50 % |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Re: Three friends, R, Y and M, each have a different number of toffees. M
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23 Dec 2023, 06:57
23 Dec 2023, 06:57
1
Let us assume that the total number of toffees is T and the number of toffees each hold is their namesake
M=T/4
Y-R=T/10, adding these 2 equations M+Y-R=7T/20
now, M+Y+R=T
subtracting above equations, (M+Y+R)-(M+Y-R)=T-7T/20
2R=13T/20
R=13T/40
Substituting the value of R in Y-R=T/10, we get Y=17T/40
so, M=T/4=0.25T, Y=17T/20=0.425T and R=13T/40=0.325T
adding the lowest values, that is M and R, we get the M+R=0.325T+0.25T=0.575T
Percentage of the total toffees held = (M+R)/T=0.575T/T=0.575= 57.5%
so, qty A is greater
M=T/4
Y-R=T/10, adding these 2 equations M+Y-R=7T/20
now, M+Y+R=T
subtracting above equations, (M+Y+R)-(M+Y-R)=T-7T/20
2R=13T/20
R=13T/40
Substituting the value of R in Y-R=T/10, we get Y=17T/40
so, M=T/4=0.25T, Y=17T/20=0.425T and R=13T/40=0.325T
adding the lowest values, that is M and R, we get the M+R=0.325T+0.25T=0.575T
Percentage of the total toffees held = (M+R)/T=0.575T/T=0.575= 57.5%
so, qty A is greater
General Discussion
Three friends, R, Y and M, each have a different number of toffees. M
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09 Nov 2024, 11:23
09 Nov 2024, 11:23
1
Take it short!
\(Y+R=1-\frac{1}{4}= \frac{3}{4}\)
\(Y-R=\frac{1}{10}\)
Y= 42.5%
R= 32.5%
M+R= 32.5%+25% = 57.5% (>50%)
Option A
\(Y+R=1-\frac{1}{4}= \frac{3}{4}\)
\(Y-R=\frac{1}{10}\)
Y= 42.5%
R= 32.5%
M+R= 32.5%+25% = 57.5% (>50%)
Option A
