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The price of a vanilla candy is $x less than twice the cost of a choco
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17 Apr 2023, 01:20
17 Apr 2023, 01:20
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The price of a vanilla candy is $x less than twice the cost of a chocolate candy. Their combined cost is less than the cost of 3 vanilla candies.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
\(\Longrightarrow\) GRE EQUATIONS
Quantity A |
Quantity B |
Cost of 4 chocolate candies |
8/3 x |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
\(\Longrightarrow\) GRE EQUATIONS
Re: The price of a vanilla candy is $x less than twice the cost of a choco
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17 Apr 2023, 07:24
17 Apr 2023, 07:24
4
A bit laborious, but it gives the answer.
VC = Vanilla Candy
CC = Chocolate Candy
The price of a vanilla candy is $x less than twice the cost of a chocolate candy.
VC = 2CC - X --- (1)
Their combined cost is less than the cost of 3 vanilla candies.
VC + CC < 3VC --- (2)
substituting (1) in (2)
2CC - X + CC < 3VC
3CC - X < 3VC
3CC - 3VC < X
3CC - 3(2CC - X) < X
3CC - 6CC + 3X < X
-3CC + 3X < X
-3CC < X - 3X
-3CC < -2X
multiplying throughout by - 1
3CC > 2X
Since Quantity B is (8/3)X, we divide throughout by 3/4 to get
3CC/(3/4) > 2X/(3/4)
4CC > 8/3X
Quantity A is greater than Quantity B
Choice A
VC = Vanilla Candy
CC = Chocolate Candy
The price of a vanilla candy is $x less than twice the cost of a chocolate candy.
VC = 2CC - X --- (1)
Their combined cost is less than the cost of 3 vanilla candies.
VC + CC < 3VC --- (2)
substituting (1) in (2)
2CC - X + CC < 3VC
3CC - X < 3VC
3CC - 3VC < X
3CC - 3(2CC - X) < X
3CC - 6CC + 3X < X
-3CC + 3X < X
-3CC < X - 3X
-3CC < -2X
multiplying throughout by - 1
3CC > 2X
Since Quantity B is (8/3)X, we divide throughout by 3/4 to get
3CC/(3/4) > 2X/(3/4)
4CC > 8/3X
Quantity A is greater than Quantity B
Choice A
Re: The price of a vanilla candy is $x less than twice the cost of a choco
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29 Nov 2024, 02:14
29 Nov 2024, 02:14
1
lets form 2 equations from the given data
assume cost of 1 vanilla candy as Cv and cost of 1 chocolate candy as Cc
1 vanilla candy is $x less than 2 times times the cost of chocolate candy
so Cv = 2Cc - x --- 1
cost of 3 vanilla candies is greater than cost of 1 vanilla candy and 1 chocolate candy
3Cv > Cc + Cv
2Cv > Cc ---2
put equation 1 in equation 2, we get
4Cc -2x > Cc
3Cc > 2x
divide by 3 and multiply by 4
we get 4Cc > (8/3) x
option A is the right answer
assume cost of 1 vanilla candy as Cv and cost of 1 chocolate candy as Cc
1 vanilla candy is $x less than 2 times times the cost of chocolate candy
so Cv = 2Cc - x --- 1
cost of 3 vanilla candies is greater than cost of 1 vanilla candy and 1 chocolate candy
3Cv > Cc + Cv
2Cv > Cc ---2
put equation 1 in equation 2, we get
4Cc -2x > Cc
3Cc > 2x
divide by 3 and multiply by 4
we get 4Cc > (8/3) x
option A is the right answer
