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In the triangle shown above, BA is parallel to CE. What is t
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19 Sep 2017, 09:49
19 Sep 2017, 09:49
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95% (00:59) correct
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In the triangle shown above, BA is parallel to CE. What is the value of x + y?
enter your value
Show: :: OA
190
Re: In the triangle shown above, BA is parallel to CE. What is t
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25 Sep 2017, 04:55
25 Sep 2017, 04:55
1
Considering the trapezoid AECB, we have that both angles A and B are 90° so that y° = 360-90-90-40 = 140. Then, considering the triangle CDE, angle E is 90 degrees, angle C is 180-y = 40 and then x = 180-90-40 = 50.
Thus, x+y = 190!
Thus, x+y = 190!
Re: In the triangle shown above, BA is parallel to CE. What is t
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25 Sep 2017, 05:20
25 Sep 2017, 05:20
1
Carcass wrote:
In the triangle shown above, BA is parallel to CE. What is the value of x + y?
enter your value
Show: :: OA
190
SInce CE parallel to BA
therefore we have angle B = angle Z = 40 degree (plz refer the diagram)
and angle A = angle E = 90 degree
NOw,
in triangle CED we have,
the sum of all angles = 180 degree
Therefore x+90 + 40 = 180 degree
or x = 50 degree.
Since angle BCD = 180 (since the two angles meet at C make up a straight line and they sum up to 180 degree)
Therefore angle y + angle Z = 180
or angle y = 180 -40 = 140 degree.
Now x+y = 140 +50 = 190 degree.
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triangle.jpg [ 30.31 KiB | Viewed 4881 times ]
