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The median of the 35 numbers in list L is 18. The mode of li
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13 Aug 2020, 01:36
13 Aug 2020, 01:36
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Question Stats:
53% (01:19) correct
46% (01:41) wrong based on 139 sessions
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The median of the 35 numbers in list L is 18. The mode of list L is not 18 and not 19.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
KUDOS for the right solution and explanation
Quantity A |
Quantity B |
The arithmetic mean of the 17 greatest numbers in list L |
19 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
KUDOS for the right solution and explanation
Re: The median of the 35 numbers in list L is 18. The mode of li
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13 Aug 2020, 13:22
13 Aug 2020, 13:22
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let my list be
x1, x2, x3, ......x17, x18, x19,.....x34, x35
THe median is x18=18
Given the mod eis not 18 nor 19
Let
x1=x2=x3=....=x17=17
and
x19=x20=x21=....=x35=18.5
So the median of the upper 17 numbers is 18.5 since all the values are 18.5
18.5<19
Choice B
Let
Let
x1=x2=x3=....=x17=17
and
x19=x20=x21=....=x35=30
So the median of the upper 17 numbers is 30 since all the values are 30
30>19
Choice A
FInal Answer: D
x1, x2, x3, ......x17, x18, x19,.....x34, x35
THe median is x18=18
Given the mod eis not 18 nor 19
Let
x1=x2=x3=....=x17=17
and
x19=x20=x21=....=x35=18.5
So the median of the upper 17 numbers is 18.5 since all the values are 18.5
18.5<19
Choice B
Let
Let
x1=x2=x3=....=x17=17
and
x19=x20=x21=....=x35=30
So the median of the upper 17 numbers is 30 since all the values are 30
30>19
Choice A
FInal Answer: D
Re: The median of the 35 numbers in list L is 18. The mode of li
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16 Aug 2020, 14:19
16 Aug 2020, 14:19
Take 18 x 7 plus 18.1 x 19.
Avg = 18.05
D
Avg = 18.05
D
