The given line passes through origin and from $\(1^{\text {st \)$ and $\(3^{\text {rd \)$ quadrant, so its equation must be of the form, $\(\mathrm{y}=\mathrm{kx}\)$, where k is any positive real number.

A point $\((r, t)\)$ lies on the line, so we get $\(t=k \times r \Rightarrow k=\frac{t}{r}\)$, which gives the equation of the line as $\(y=\frac{t}{r}(x)\)$


Also the point $\((-r, s)\)$ lies on the equation, we get $\(s=\frac{t}{r}(-r) \Rightarrow-s=t\)$

Hence column A quantity equals column B , so the answer is (C).