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A box contains six balls numbered 1 to 6. Two balls are selected fro [#permalink]
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A box contains 6 balls numbered 1 to 6 which implies all balls are different.

Two balls are selected from the box one after the other with replacement and the sum of the numbers on the balls picked is 10 , so the total number of possible outcomes is $\(\{(4,6),(6,4),(5, 5)\}\)$ i.e. 3 only.

Since only 2 out of 3 outcomes have a 6 , the probability that one of the balls picked was numbered 6 is $\(\frac{2}{3}\) \((\because Probability of an event = \frac{Favourable number of outcomes }{Total number of outcomes}\)

Hence the answer is (E).
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A box contains six balls numbered 1 to 6. Two balls are selected fro [#permalink]
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