We only know that the slope of line $l\(=-\frac{1}{2}\)$ which can be true for different lines.

For example line having x -intercept $\((-1) \& \mathrm{y}\)$-intercept $\((-2)\)$ would have slope $\(-\frac{1}{2}\)$, so column A gets higher quantity but if we consider $\(x\)$-intercept $\(1 \& y\)$-intercept 2 , the slope still remains the same and column $\(B\)$ gets higher value.

(Note: - the slope of a line in the intercept form is $\(\left.-\frac{(y-\text { int ercept })}{(x-\text { intercept })}\right)\)$
Hence a unique comparison cannot be formed between column A \& column B quantity, so the answer is (D).