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Re: The random variable x has the following continuous probabil
[#permalink]
24 Dec 2024, 10:35
24 Dec 2024, 10:35
I think that for me is easier to understand with an integral:
I cannot upload the image
Compute the integral:
∫0m(2−x) dx=[2x−x22]0m.
∫0m(2
−x)dx=[2
x−2x2]0m.
At x=mx=m:
2m−m22=12.
2
m−2m2=21.
I cannot upload the image
Compute the integral:
∫0m(2−x) dx=[2x−x22]0m.
∫0m(2
−x)dx=[2
x−2x2]0m.
At x=mx=m:
2m−m22=12.
2
m−2m2=21.
Re: The random variable x has the following continuous probabil
[#permalink]
24 Dec 2024, 15:53
24 Dec 2024, 15:53
Expert Reply
Even thoguh the approach is effective I do not think the GRE contemplates integral to reach a solution
The random variable x has the following continuous probabil
[#permalink]
03 Jan 2025, 13:42
03 Jan 2025, 13:42
Sorry, I went through the thread but I still don't understand what is happening. My main doubts are-
1. Option C and E are literally the same so is this some typo or is this intentionally there and we have to choose C for some reason. Could someone please explain this further?
2. The median point should be 1/√2? The way I arrived at this was:
a) Draw an altitude from the origin to the Hypotenuse and since the total length of it is 2 (calculated using distance formula), it would be divided in two equal parts of 1 ( I am unable to share the attachment because of forum's rules). So, using 45-45-90 rule we would find out the length of the altitude to be 1 then again we draw an altitude to the x-axis where previous altitude becomes the side of the new Isosceles triangle and after doing some calculations we would get √2/2 as the length on x-axis for the 50% value.
Where am I going wrong here? I don't get it because I can write 1/√2 as √2^-1 but I am confused with 2 similar options here and explanations given by other members here that don't match with my reasoning. Please help me. Thanks!
1. Option C and E are literally the same so is this some typo or is this intentionally there and we have to choose C for some reason. Could someone please explain this further?
2. The median point should be 1/√2? The way I arrived at this was:
a) Draw an altitude from the origin to the Hypotenuse and since the total length of it is 2 (calculated using distance formula), it would be divided in two equal parts of 1 ( I am unable to share the attachment because of forum's rules). So, using 45-45-90 rule we would find out the length of the altitude to be 1 then again we draw an altitude to the x-axis where previous altitude becomes the side of the new Isosceles triangle and after doing some calculations we would get √2/2 as the length on x-axis for the 50% value.
Where am I going wrong here? I don't get it because I can write 1/√2 as √2^-1 but I am confused with 2 similar options here and explanations given by other members here that don't match with my reasoning. Please help me. Thanks!
