We have 2 girls sit at the 2 ends, therefore we have P(3,2) = 6 (order is important here so we can't use C). That will leave 4 people, 3 boys and 1 girl in the middle. Since they can sit anywhere, in whatever arrangment, we have P(4,4) or 4! = 24. Total possible arrangement is 6*24 = 144. Answer is D.

For the two seats at either end, there are three choices (as there are three girls) for one end and two choices (since two girls are left after one already sits at one end) for the other end. Regarding the four seats in the middle, there are 4! (4 factorial) = 24 ways to arrange the remaining girl and the three boys. Consequently, the total number of ways to seat the six children with the two girls at either end of the bench is calculated as 3 x 2 x 24 = 144.

6 seats

_ _ _ _ _ _

Ends can be filled like

3 _ _ _ _ _ 2 (seating girls. First seat can be filled in 3 ways since 3 girls are available. last seats can be filled in 2 ways since 1 girl has already taken the first seat)

Remaining are 3 boys and 1 girl. So they could be seated in the seats other than the last seats like

3 4 3 2 1 2

Multiplying the number of ways: 3*4*3*2*1*2 = 144