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y<1, y different from zero
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02 Dec 2018, 05:14
02 Dec 2018, 05:14
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\(y<1\)
\(y\neq 0\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given
\(y\neq 0\)
Quantity A |
Quantity B |
\(y\) |
\(y^2\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given
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Re: y<1, y different from zero
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02 Dec 2018, 07:55
02 Dec 2018, 07:55
1
Carcass wrote:
\(y<1\)
\(y\neq 0\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given
\(y\neq 0\)
Quantity A |
Quantity B |
\(y\) |
\(y^2\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given
Let's test some values
Case i: y = 0.5
We get:
Quantity A: 0.5
Quantity B: (0.5)² = 0.25
In this case, Quantity A is GREATER
Case ii: y = -1
We get:
Quantity A: -1
Quantity B: (-1)² = 1
In this case, Quantity B is GREATER
Answer: D
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Re: y<1, y different from zero
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09 Jan 2025, 06:29
09 Jan 2025, 06:29
1
Here They haven't mentioned Y is an Integer. The constraint is just that y should be less than 1 and y can't be 0.
then y can be say -4 then Quant B is greater
also if y is 0.4 then Quant B is 0.16 then Quant A > Quant B .
Hence Option D
then y can be say -4 then Quant B is greater
also if y is 0.4 then Quant B is 0.16 then Quant A > Quant B .
Hence Option D
