We have assumed the measure of angle Q as x degrees.

As the perimeter of triangle PQR is given as 32 , we get $\(\mathrm{PQ}=32-(13+12)=32-25=7\)$

Now, we have $\(\mathrm{PR}^2=13^2=169\)$ which is less than $\(\mathrm{QR}^2+\mathrm{PQ}^2=12^2+7^2=144+49=193\)$ which implies the measure of angle Q i.e. x is less than 90 degrees.

[Note: - In a triangle say $\(\mathrm{ABC}, \triangle \mathrm{C}^2=\mathrm{AB}^2+\mathrm{BC}^2 \Leftrightarrow \angle \mathrm{~B}=90^{\circ}, \mathrm{AC}^2>\mathrm{AB}^2+\mathrm{BC}^2 \Leftrightarrow \angle \mathrm{~B}>90^{\circ}\)$ $\(\left.\& \mathrm{AC}^2<\mathrm{AB}^2+\mathrm{BC}^2 \Leftrightarrow \angle \mathrm{~B}<90^{\circ}\right]\)$

Hence column $\(B\)$ has higher quantity when compared with column $\(A\)$, so the answer is (B).