You are right, I made a typo!

We can solve this question using matching operations

Given:
Quantity A: (98^7)/(7^63)
Quantity B: (2^7)/(7^49)

Multiply both quantities by 7^63 to get:
Quantity A: 98^7
Quantity B: (2^7)(7^14)

Rewrite 7^14 as (7^7)(7^7) to get:
Quantity A: 98^7
Quantity B: (2^7)(7^7)(7^7)

A nice rule says (a^k)(b^k) = (ab)^k

Apply this rule to quantity B to get:
Quantity A: 98^7
Quantity B: (2 x 7 x 7)^7

Simplify to get:
Quantity A: 98^7
Quantity B: 98^7

Answer: C

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Nice .. it was hard to imagine that.. great

How do you go from 98^7 to 7^14*2^7?

We use the rule that says \((abc)^n = a^nb^nc^n\)

\(98 = (7)(7)(2)\)

So, \(98^7 = [(7)(7)(2)]^7\)

So, according to the above rule, we can write: \(98^7 = (7^7)(7^7)(2^7)\)

Since \((7^7)(7^7) = 7^{14}\), we can write: \(98^7 = (7^{14})(2^7)\)

Does that help?

that's perfect thanks!

Thank you greenlight test prep. best explanation!

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